IP Addressing

Correct Answer: APIPA assigned address

The IPv4 address 169.254.5.183 is an automatically assigned address, known as an Automatic Private Internet Protocol Addressing (APIPA) address. This is generally given to a computer when it is set to obtain an IP address automatically but was unable to receive an IP address from a Dynamic Host Configuration Protocol (DHCP) server. This address lets the computer communicate with other devices that have addresses in the same APIPA range (169.254.0.0 to 169.254.255.255), but it cannot connect to network resources outside this range, hence the reported issue. The other options are incorrect. A static IP address is manually assigned and wouldn't likely involve this range, a properly assigned DHCP address would let the computer connect with network resources, and a loopback address (127.0.0.1) is used for internal testing of the computer's network interface.

Correct Answer: 255.255.255.240

The correct subnet mask for creating 16 subnets from a Class C network is 255.255.255.240.

To understand this, let's break it down:

1. A Class C network has a default subnet mask of 255.255.255.0.
2. To create subnets, we need to borrow bits from the host portion of the address.
3. To create 16 subnets, we need 4 bits (2^4 = 16).
4. Borrowing 4 bits from the last octet gives us: 11110000 in binary.
5. 11110000 in binary is equal to 240 in decimal.

Therefore, the correct subnet mask is 255.255.255.240.

The other options are incorrect:

255.255.255.224 would create 8 subnets (not enough).
255.255.255.248 would create 32 subnets (too many).
255.255.255.192 would create 4 subnets (not enough).

Understanding subnet masks is crucial for network administrators to efficiently divide networks and manage IP addressing schemes.

Correct Answer: 254

The subnet mask of 255.255.255.0 provides 256 potential IP addresses (the total number of IPv4 addresses in one byte is 2 raised to the power of 8 equals 256). However, because the first address describes the network and the last one is reserved for the broadcast address, these cannot be used to host devices. Therefore, the maximum number of hosts that Jim can have in the same subnet would be 256 - 2 equals 254. This makes '254' the correct answer. The other answers are incorrect: '255' only subtracts the network address yet includes the broadcast address, '256' neglects to subtract both the network and broadcast addresses, and '512' is simply too high for a subnet mask of 255.255.255.0.